A 9.40 L container holds a mixture of two gases at 37 °C. The partial pressures...

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Question

A 9.40 L container holds a mixture of two gases at 37 °C. The partial pressures of gas A and as B. respectively, are 0.323 at

Answer 1

Answer #1

first calculate partial pressure of third gas

assume third gas = C

P_C = nRT / V

P_C = 0.170 x 0.0821 x 310 /9.40

P_C = 0.460 atm

now

P_total = P_A + P_B + P_C

P_total = 0.323 + 0.852 + 0.460

P_total = 1.635 atm

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Answer 2

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