Concentration of sodium in sample = 0.078 M
Explanation
When Na emission signal values are plotted against Na concentration values, we get a straight line with equation : y = 40.455x - 0.025
Given : emission signal of sample = 3.13 = y
From the equation of line, x = (y + 0.025) / 40.455
x = (3.13 + 0.025) / 40.455
x = (3.155) / 40.455
x = 0.0780 M
25.00 mL of serum was pipetted into each of five 50 mL volumetric flasks. Varying additions...
please answer this question with full working out 25.00 mL of serum was pipetted into each of five 50 mL volumetric flasks. Varying additions of 2.934 M NaCl standard were made and the total volumes made up to 50 mL. The samples were analysed by sodium emission spectroscopy. Flask Volume of standard (ml) Na emission signal (mv) 3.13 1.000 5.40 2.000 7.89 3.000 10.30 4.000 12.48 600 Determine the concentration of sodium in the sample. Unit of concentration is M,...
(20 points) Students performed an experiment in which each flask contained 2.50 ml of with varying additions of 2.640 M NaCl standard, and a total volume of 50.00 mL. Prepare standard addition graph and find (Na+) in the serum. FLASK VSTD, ML Na Signal, my 1.000 2.000 3.000 3.13 5.40 7.89 10.30 12.48 4.000