Solution contains Serum + Standard.
In the flask 1, only serum is present and the signal is due to serum only.
In all other flasks, the signal is due to combination of serum and NaCl.
The value of the emission signal for the flask one is subtracted from the value of emission signals for flasks 2 to 5.
The resulting values gives the emission signal due to standard present in flasks 2 to 5.
This value is plotted against the volume of standard.
The graph is as shown:
The equation of the graph is,
y = 2.36 x -0.01
Substitute, y = 3.13 in the above equation
3.13 = 2.36 x - 0.01
x = 1.33
This is the volume of standard (mL) which will correspond to sodium ion concentration in the serum.
The sodium ion concentration in the serum will be = 2.640 mole/L x 1.33 mL/2.5 mL = 1.40 M
(20 points) Students performed an experiment in which each flask contained 2.50 ml of with varying...
25.00 mL of serum was pipetted into each of five 50 mL volumetric flasks. Varying additions of 2.923 M NaCl standard were made and the total volumes made up to 50 ml. The samples were analysed by sodium emission spectroscopy. Flask Volume of standard (mL) Na emission signal (mv) 3.13 1.000 5.40 2.000 7.89 3.000 10.30 4.000 12.48 Determine the concentration of sodium in the sample. Unit of concentration is M, but please do not type this in.
please answer this question with full working out 25.00 mL of serum was pipetted into each of five 50 mL volumetric flasks. Varying additions of 2.934 M NaCl standard were made and the total volumes made up to 50 mL. The samples were analysed by sodium emission spectroscopy. Flask Volume of standard (ml) Na emission signal (mv) 3.13 1.000 5.40 2.000 7.89 3.000 10.30 4.000 12.48 600 Determine the concentration of sodium in the sample. Unit of concentration is M,...