here,
the mass of ball ,m = 1.12 kg
initial speed , u = 16.81 m/s
the initial height , h0 = 1 m
let the maximum height gained be h
using conservation of energy
0.5 * m * u^2 + m * g * h0 = m * g * h
0.5 * 15.81^2 + 9.81 * 1 = 9.81 * h
solving for h
h = 13.74 m
the maximum height gained is 13.74 m
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