Homework Answers
Fe in Fe+2 has oxidation state of +2
Fe in Fe+3 has oxidation state of +3
So, Fe in Fe+2 is oxidised to Fe+3
Mn in MnO4- has oxidation state of +7
Mn in Mn+2 has oxidation state of +2
So, Mn in MnO4- is reduced to Mn+2
Reduction half cell:
MnO4- + 5e- --> Mn+2
Oxidation half cell:
Fe+2 --> Fe+3 + 1e-
Balance number of electrons to be same in both half reactions
Reduction half cell:
MnO4- + 5e- --> Mn+2
Oxidation half cell:
5 Fe+2 --> 5 Fe+3 + 5e-
Lets combine both the reactions.
MnO4- + 5 Fe+2 --> Mn+2 + 5 Fe+3
Balance Oxygen by adding water
MnO4- + 5 Fe+2 --> Mn+2 + 5 Fe+3 + 4 H2O
Balance Hydrogen by adding H+
MnO4- + 5 Fe+2 + 8 H+ --> Mn+2 + 5 Fe+3 + 4 H2O
This is balanced chemical equation in acidic medium
Sum of coefficients of all products = 1 + 5 + 4 = 10
Answer: 10
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