Part A How ta' from . .7.00 μ0 poi, charge nuat a 230 Aad point charge...

Question

Question

Answer 1

Answer #1

Given q₁ = - 7.00 $\mu$ C = -7.00 x 10^-6 C

q₂ = 2.30 $\mu$ C = 2.30 x 10^-6 C

Potential energy U = - 0.5 J

But U = K q1q2 / r

hence r = K q1q2 / U

= (9 x 10⁹ x -7.00 x 10^-6 x 2.30 x 10^-6 ) / -0.5

= 289.8 x 10^-3 m

= 0.289 m

= 0.29 m

Answer 2

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