An electron is to be accelerated in a uniform electric field having a strength of 1.60...

Question

Question

Answer 1

Answer #1

a) then Energy KE = q(deltaV )

deltaV = E.d = 1.60 * 10^6 * 0.790 = 1264000 V

KE = e * 1264000 V = 1264 keV Answer

b) now KE = 50 GeV = 50 * 10^9 eV

kE = q (Ed)

50 * 10^9 eV = 1e * 1.60 * 10^6 V/m * L

L = 31250 m = 31.25 km Answer

I hope help you !!

Answer 2

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