At equilibrium:
SrCO3 <----> Sr2+ + CO32-
s s
Ksp = [Sr2+][CO32-]
9.3*10^-10=(s)*(s)
9.3*10^-10= 1(s)^2
s = 3.05*10^-5 M
Molar mass of SrCO3 = 147.63 g/mol
Molar mass of SrCO3= 147.63 g/mol
s = 3.05*10^-5 mol/L
To covert it to g/L, multiply it by molar mass
s = 3.05*10^-5 mol/L * 147.63 g/mol
s = 4.502*10^-3 g/L
Answer: 4.50*10^-3 g/L
17.35 Strontianite (strontium carbonate) is an important mineral of strontium. Calculate the solubility (in g/L) of...
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