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PLEASE HELP! In an acid-base neutralization reaction 87.13mL of a 0.200M Ba(OH)2 solution reacts with 42.16mL...

PLEASE HELP! In an acid-base neutralization reaction 87.13mL of a 0.200M Ba(OH)2 solution reacts with 42.16mL of H3PO4 to reach the equivalent point. What is the molarity of the H3PO4?

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Answer #1

Baz(paus 2 H3 Poy+3Ba(oH) +61H,0 BaloH)2 H3 Pou M,2 M20,2 M V,42.16m n2 =3 (don sn) M,Vi H2V2 n2 M2 V2ni Mi- o.2x 87. 13 X 2

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