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Acid-base titration questions. Please help! Thanks.

2. Given that 20.00 mL of phosphoric acid solution required 15.50 mL of 0.200M NaOH for the first equivalent point. What is t

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Answer #1

2)

At first equivalence H3PO4 + NaOH -----> NaH2PO4 + H2O is the balanced equation .
Thus
meq of acid = meq of base
20x M = 15.5x0.2
Thus
molarity of acid = 0.155 M

3)At first equivalence H3PO4 + NaOH -----> NaH2PO4 + H2O is the balanced equation .
Thus
meq of acid = meq of base
25x M = 18.27x0.01
Thus
molarity of acid = 0.00738M

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