Titration of 25.00 mL of an unknown diprotic acid solution required 15.09 mL of 0.10 M NaOH to reach the first equivalence point and 29.82 mL of 0.10 M NaOH to reach the second equivalence point. What is the concentration of the diprotic acid solution?
assume diprotic acid = H2A
H2A + 2NaOH -----------> Na2A + 2H2O
millimoles of NaOH required to reach second equivalence point = 29.82 x 0.10 = 2.982
2.982 / 2 = 1.491 millimoles diprotic acid must be present.
1.491 = 25.0 x M
M = 0.060 M
[H2A] = 0.060 M
Titration of 25.00 mL of an unknown diprotic acid solution required 15.09 mL of 0.10 M...
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