Q4. Let the diprotic acid be H2A
The balanced reaction is : H2A (aq) + 2 NaOH (aq) Na2A (aq) + 2 H2O (l)
concentration NaOH = 1.0 M
volume NaOH = 13.48 mL = 0.01348 L
moles NaOH added = (concentration NaOH) * (volume NaOH)
moles NaOH added = (1.0 M) * (0.01348 L)
moles NaOH added = 0.01348 mol
moles H2A present = (moles NaOH added) * (1 mole H2A / 2 moles NaOH)
moles H2A present = (0.01348 mol) * (1/2)
moles H2A present = (0.01348 mol) * (0.5)
moles H2A present = 0.00674 mol
molar mass of acid = (mass of acid) / (moles of acid)
molar mass of acid = (0.79 g) / (0.00674 mol)
molar mass of acid = 117.2 g/mol
Unknown acid can be maleic acid H2C4H2O4 (molar mass 116 g/mol)
4 please 3. When titrating 25.0 mL of 0.10 M H;SO4 with 0.10 M NaOH, how...
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