Suppose you are titrating a 25.0 mL aqueous solution of HNO2 (Ka = 4.6 × 10−4) with 0.150 M NaOH at 25 °C. You find that 23.5 mL of NaOH are required to reach the equivalence point. Please determine the pH at the equivalence point.
Suppose you are titrating a 25.0 mL aqueous solution of HNO2 (Ka = 4.6 × 10−4)...
7. Calculate the pH of the solution obtained by titrating 50.0 mL of 0.100 M HNO2(aq) with 0.150 M NaOH(aq) to the equivalence point. Take Ka = 5.6 x 10 - M for HNO2(aq).
Calculate the pH of the solution obtained by titrating 40 ml of 0.35 M HNO2(aq) with 0.4 M NaOH(aq) to the equivalence point. Take Ka= 4.6x10^M.
A 40.0 mL sample of 0.150 M HNO2 (Ka = 4.60 x 10-4) is titrated with 0.200 M KOH. Calculate: a. the pH after adding 10.00 mL of KOH b. the pH at one-half the equivalence point c. the pH after adding 20.00 mL of KOH d. the volume required to reach the equivalence point e. the pH at the equivalence point f. the pH after adding 45.00 mL of KOH
You have 75.0 mL of 0.150 M HNO2 (Ka = 4.50 x 10-4) to which you add 50.0 mL of 0.150 M NaOH. What will be the resulting pH of the solution?
50.0 mL of 0.090 M nitrous acid (HNO2, Ka = 7.1 x 10-4), is titrated with 0.100 M NaOH, requiring 45.0 mL of strong base to reach the equivalence point. (a) What will be the pH after 35.0 mL of NaOH have been added? (b) What will be the pH at the equivalence point? (c) What will be the pH after 60.0 mL of NaOH have been added?
A student performs a titration of 25.0 mL of 0.100 M lactic acid (HC3H5O3), using 0.050 M sodium hydroxide (NaOH). The Ka for lactic acid is 1.4 x 10-4. a) (10 points) What is the pH of the solution after the addition of 23.5 mL of sodium hydroxide solution? b) (4 points) How many milliliters of NaOH are required to reach the equivalence point? c) (4 points) Write the chemical reaction that will determine the pH of the solution at...
1. You are titrating a 100.0 mL solution of 0.050 M HBrwith a 0.150 M solution of KOH. What will be the pH after the addition of 25.0 mL KOH? 2. You titrate 250 mL of 0.250 M acetic acid (Ka= 1.8 x 10-5) with 50.0 mL of 0.350 M NaOH. What is the pH of this solution? 3. For the titration in question 2, what would be the Kaof an ideal indicator.
4 please
3. When titrating 25.0 mL of 0.10 M H;SO4 with 0.10 M NaOH, how many mL of NAOH will you have added to reach the first equivalence point? How many mL of NaOH will you have added to reach the second equivalence point? Show calculations. (4 pts) 4. A student completes a titration of an unknown diprotic acid. In their experiment, 0.79 g of the acid was dissolved in 250.0 mL of DI water. It required 13.48 mL...
A 25.0 mL sample of 0.150 M formic acid is titrated with a 0.150 M NaOH solution. What is the pH at the equivalence point? The Ka of formic acid is 1.8 ⋅ 10-4.
A 50.0 mL sample of 0.25 M formic acid (HCOOH) aqueous solution is titrated with 0.125 M NaOH solution. Ka of HCOOH = 1.7 x 10−4. a. Calculate the pH of the solution after 50 mL of NaOH solution has been added. b. How many mL of 0.125 M NaOH need to be added to the sample to reach the equivalence point? What is the pH at the equivalence point?