7. Calculate the pH of the solution obtained by titrating 50.0 mL of 0.100 M HNO2(aq)...
Calculate the pH of the solution obtained by titrating 40 ml of 0.35 M HNO2(aq) with 0.4 M NaOH(aq) to the equivalence point. Take Ka= 4.6x10^M.
Calculate the pH of the solution obtained by titrating 40 ml of 0.35 M HNO3(aq) with 0.4 M NaOH(aq) to the equivalence point. Take K = 4.6x10^M.
(10 marks) Calculate the pH after titrating 50.0 mL of a 0.100 M weak base solution (Kb = 7 x10-9) with: 0.200 M HBr to the equivalence point b. 50.0 mL of 0.200 M HBr
Suppose you are titrating a 25.0 mL aqueous solution of HNO2 (Ka = 4.6 × 10−4) with 0.150 M NaOH at 25 °C. You find that 23.5 mL of NaOH are required to reach the equivalence point. Please determine the pH at the equivalence point.
A volume of 50.0 mL of 0.100 M CH3COOH(aq) is titrated with 0.100 M NaOH(aq). What is the pH at the equivalence point? (Ka for CH3COOH = 1.8 × 10–5) (1) 7 (2) 5.28 (3) 8.72 (4) 6.34 (5) 4.15
50.0 mL of 0.090 M nitrous acid (HNO2, Ka = 7.1 x 10-4), is titrated with 0.100 M NaOH, requiring 45.0 mL of strong base to reach the equivalence point. (a) What will be the pH after 35.0 mL of NaOH have been added? (b) What will be the pH at the equivalence point? (c) What will be the pH after 60.0 mL of NaOH have been added?
What is the pH at the equivalence point in the titration of 50.0 mL of 0.100 M hydrofluoric acid, HF, (Ka = 7.2 x 10-4) with 0.100 M NaOH?
What is the pH of a solution of 40.0 mL of 0.100 M acetic acid (Ka = 1.8 x 10-5) after 50.0 mL of 0.100 M NaOH has been added? Calculate the concentration of dissolved Ba2+ ions when BaSO4 is added to water at 25°C. Кsp? = 1.10 x 10-10 A particular saturated solution of silver chromate (Ag2CrO4), has [Ag+] = 5.0 x 10 Mand (CrO4) = 4.4 x 10M. What is value Ksp for silver chromate? As a result...
50.0 mL of 0.150 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
Calculate the pH at the equivalence point in titrating 0.100 M solution of Benzoic Acid (C6H5COOH) with 0.800 M NaOH.