You have 75.0 mL of 0.150 M HNO2 (Ka = 4.50 x 10-4) to which you add 50.0 mL of 0.150 M NaOH. What will be the resulting pH of the solution?
50.0 mL of 0.090 M nitrous acid (HNO2, Ka = 7.1 x 10-4), is titrated with 0.100 M NaOH, requiring 45.0 mL of strong base to reach the equivalence point. (a) What will be the pH after 35.0 mL of NaOH have been added? (b) What will be the pH at the equivalence point? (c) What will be the pH after 60.0 mL of NaOH have been added?
Suppose you are titrating a 25.0 mL aqueous solution of HNO2 (Ka = 4.6 × 10−4) with 0.150 M NaOH at 25 °C. You find that 23.5 mL of NaOH are required to reach the equivalence point. Please determine the pH at the equivalence point.
A 40.0 mL sample of 0.150 M HNO2 (Ka = 4.60 x 10-4) is titrated with 0.200 M KOH. Calculate: a. the pH after adding 10.00 mL of KOH b. the pH at one-half the equivalence point c. the pH after adding 20.00 mL of KOH d. the volume required to reach the equivalence point e. the pH at the equivalence point f. the pH after adding 45.00 mL of KOH
7. Calculate the pH of the solution obtained by titrating 50.0 mL of 0.100 M HNO2(aq) with 0.150 M NaOH(aq) to the equivalence point. Take Ka = 5.6 x 10 - M for HNO2(aq).
a) A 41.0 mL sample of 0.194 M HNO2 is titrated with 0.220 M KOH. (Ka for HNO2 is 4.57×10−4.) Determine the pH at the equivalence point for the titration of HNO2 and KOH. b) A 50.0-mL sample of 0.200 M sodium hydroxide is titrated with 0.200 M nitric acid. Calculate the pH of the solution, after you add a total of 56.7 mL 0.200 M HNO3.
50.0 mL of 0.150 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
1. You are titrating a 100.0 mL solution of 0.050 M HBrwith a 0.150 M solution of KOH. What will be the pH after the addition of 25.0 mL KOH? 2. You titrate 250 mL of 0.250 M acetic acid (Ka= 1.8 x 10-5) with 50.0 mL of 0.350 M NaOH. What is the pH of this solution? 3. For the titration in question 2, what would be the Kaof an ideal indicator.
What is the resulting pH when you combine 75.0 mL of a 0.12 M solution of NaOH and 83.0 mL of a 3.9 M solution of acetic acic acid has a Ka = 1.8 x 10-5. HINT: Find the concentrations first, then plug into an ice table. Make sure you know the total volumel
IV. Acid-Base Titration (15 points). A 50 mL of 0.200 M HNO2, (Ka= 4.0 x 10) solution is titrated with 0.200 M NaOH. Find the pH before titration and after 25 mL, 50 mL, and 60 mL of NaOH has been added.
You have nitrous acid, HNO2, Ka=4.0 x 10-4 Calculate the pH of the solution and calculate the concentration of HNO2 and its conjugate base in a 0.025 M HNO2 Solution. Please please show all work!