A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with NaOH. If the titration required 17.73 mL of 0.1036 M NaOH to completely neutralize the acid, calculate the concentration (in M) of the weak acid in the sample. (a) 9.184 x 10‒4 M (b) 3.674 x 10‒2 M (c) 7.304 x 10‒2 M (d) 7.347 x 10‒2 M (e) 1.469 x 10‒1 M
A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A)...
6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added, the pH of the resulting solution was 6.70. After 50.0 mL of NaOH was added, the pH of the solution was 8.00. What are the values of Ka1 and Ka2?
6. A student titrated 50.0 mL of the 0.10 M unknown diprotic H2A with 0. 10 M NAOH. After 25.0 mL of NaOH was added,...
Titration of 25.00 mL of an unknown diprotic acid solution required 15.09 mL of 0.10 M NaOH to reach the first equivalence point and 29.82 mL of 0.10 M NaOH to reach the second equivalence point. What is the concentration of the diprotic acid solution?
1.639 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1032 M NaOH. The titration endpoint is reached after 0.00414 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures.
A 25.00 mL sample of an unknown sulfuric acid solution is titrated with 29.84 mL of a sodium hydroxide solution with a concentration of 0.150 M NaOH. What is the concentration of the sulfuric acid solution? H.SO.(aq) + 2NaOH(aq) → Na2SO4 (aq) + 2 H2O(1) Show your work Final Answer
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
A 25.00 mL solution of H2SO4 of unknown concentration was titrated with a 3.15 M NaOH solution. What is the concentration of the H2SO4 solution if 36.01 mL of the NaOH solution is required neutralize the acid solution?
0.001742 mol of NaOH was required to neutralize a sample containing the unknown diprotic acid, H, A. How many moles of H2A were present in the sample?
1) A solution of a weak monoprotic acid of unknown concentration was titrated with 0.23 M NaOH. If a 100.-mL sample of the acid solution required exactly 10. mL of the NaOH solution to reach the equivalence point, what was the original concentration of the weak acid? 2) During the titration on problem (2B), after 5.0 mL of NaOH addition, the pH = 3.68. What is the Ka of the weak acid? please show steps i have an exam tomorrow
Weak Acid Titration When a 14.0 mL sample of a monoprotic weak acid is titrated with 0.10 M NaOH, it generates the titration curve shown below. Weak Acid titrated with 0.10 M NaOH pH Volume of 0.10 M NaOH a) What is the molar concentration of the original sample of weak acid? х М b) What is the ka for this weak acid?
Question 6 (1 point) 1.681 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1047 M NaOH. The titration endpoint is reached after 0.00411 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures. Your Answer: Answer units