Diprotic acid contain two H+ ions hence it require double the moles of NaOH in compare to its own moles. Hence,
Moles of H2A = moles of NaOH/2
= 0.001742/2
= 0.000871 moles
0.001742 mol of NaOH was required to neutralize a sample containing the unknown diprotic acid, H,...
A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with NaOH. If the titration required 17.73 mL of 0.1036 M NaOH to completely neutralize the acid, calculate the concentration (in M) of the weak acid in the sample. (a) 9.184 x 10‒4 M (b) 3.674 x 10‒2 M (c) 7.304 x 10‒2 M (d) 7.347 x 10‒2 M (e) 1.469 x 10‒1 M
Sulfurous acid (H2SO3) is a diprotic acid. How many milliliter of 0.1208 M NaOH is required to neutralize 0.3121 L of 0.1112 M sulfurous acid? [Hint: How many moles of NaOH would react with 1 mole of sulfurous acid?]
9) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction:HC2H3O2(aq) + NaOH(aq) → NaC2H;O2(aq) + H2O(1). How many moles of NaOH were used in this titration? Report the correct number of significant figures, and report the units. 10) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction: HC2H302(aq) + NaOH(aq) → NaC2H:02(aq)...
please show work 22. A 0.670 g sample of an unknown diprotic acid required 25.00 mL of 0.160 M NaOH to titrate it. What is the molar mass (g mol-') of unknown acid? A. 0.167 g mol-' B. 335 g mol-' C. 180. g mol-' D. 167.5 g mol' E. 0.335 g mol-'
4. Knowing that one mole of KHP, C3H5O4K, reacts with one mole of NaOH, what mass of KHP is required to neutralize 30.0 mL of the 0.10 M NaOH solution? 5. If 24.5 mL of the 0.10 M NaOH solution is required to reach the endpoint in a titration with an unknown monoprotic acid, how many moles of the acid were present?
2. A 0.2349 g sample of an unknown acid requires 33.66 mL of 0.1086 M NaOH for neutralization to a phenolphthalein end point. There are 0.42 mL of 0.1049 M HCI used for back-titration. a. How many moles of OH- are used? moles OH moles H b. How many moles of H+ from HCI? moles H c. How many moles of H+ are there ins solid acid? (Eq. 5) g/mol d. What is the molar mass of the unknown acid?...
ascorbic acid is a diuretic acid. what volume of .120 M NaOH is required to neutralize 10.00 ml of .180 M H2C6H6O6 in an acid base titration a how many moles of ascorbic acid will be neutralized b how many moles of NaOH are required in neutralization c what volume of the NaOH solution contains this number of moles?
6. Titration of a 50.00 mL solution of an unknown diprotic acid required 35.95 mL of 0.1367 M sodium hydroxide to reach the second equivalence point. What was the initial concentration of the unknown acid . A 0.8752 g sample of unknown containing potassium hydrogen phthalate (KHP) required 28.23 mL of a 0.1037 M NaOH for neutralizatjon. What is the mass percentage of KHP in the sample?
11.83 mL of 0.5008 M NaOH was required to neutralize 25.00 mL of HCl with unknown molarity. How many moles per liter of NaOH was used?
| A 0.458 g sample of a diprotic acid is dissolved in water and titrated with 0.170 M NaOH. What is the molar mass of the acid if 37.4 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: g/mol