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please show work 22. A 0.670 g sample of an unknown diprotic acid required 25.00 mL...
1.639 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1032 M NaOH. The titration endpoint is reached after 0.00414 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures.
A 0.541 g sample of a diprotic acid is dissolved in water and titrated with 0.160 M NaOH. What is the molar mass of the acid if 30.6 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: _____ g/mol
A 0.521 g sample of a diprotic acid is dissolved in water and titrated with 0.160 M NaOH. What is the molar mass of the acid if 40.4 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: g/mol
1.639 g of an unknown diprotic acis are used to make a 100.00 mL solutiob. Then 25.00 mL of this solution is trasferred to an Erlenmeyer flask and is titrated with 0.1008 M NaOH. The titration endpoint is reaxhed after 0.00432 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct nuber of significat figures 1.639 g of an unknown diprotic acid are used to make a...
Question 6 (1 point) 1.681 g of an unknown diprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an Erlenmeyer flask and is titrated with 0.1047 M NaOH. The titration endpoint is reached after 0.00411 mol of NaOH is added using the burette. What is the molar mass of the diprotic acid? Provide your answer to the correct number of significant figures. Your Answer: Answer units
Titration of 25.00 mL of an unknown diprotic acid solution required 15.09 mL of 0.10 M NaOH to reach the first equivalence point and 29.82 mL of 0.10 M NaOH to reach the second equivalence point. What is the concentration of the diprotic acid solution?
A 0.155 g sample of a diprotic acid of unknown molar mass is dissolved in water and titrated with 0.1268 M NaOH. The equivalence point is reached after adding 13.2 mL of base. What is the molar mass of the unknown acid?
| A 0.458 g sample of a diprotic acid is dissolved in water and titrated with 0.170 M NaOH. What is the molar mass of the acid if 37.4 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: g/mol
A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with NaOH. If the titration required 17.73 mL of 0.1036 M NaOH to completely neutralize the acid, calculate the concentration (in M) of the weak acid in the sample. (a) 9.184 x 10‒4 M (b) 3.674 x 10‒2 M (c) 7.304 x 10‒2 M (d) 7.347 x 10‒2 M (e) 1.469 x 10‒1 M
A 0.401 g sample of a diprotic acid is dissolved in water and titrated with 0.130 M NaOH. What is the molar mass of the acid if 31.3 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: g/mol