1.) 20.00 mL of 0.11 M benzoic acid (C6H5COOH, Ka = 6.3x10-5) is titrated with 0.25 M NaOH. What volume of base is required to reach the equivalence point in the titration?
2.) Calculate pH at each of the following points in the titration.
a) 4.00 mL
b) 8.80 mL
1.) 20.00 mL of 0.11 M benzoic acid (C6H5COOH, Ka = 6.3x10-5) is titrated with 0.25...
You are given a 30.0mL sample of 0.20M C6H5COOH(aq) (benzoic acid). Ka for benzoic acid is 6.5x10-5. a) what is the initial pH of the 0.20M C6H5COOH(aq) solution? b) what is the pH after the addition of 15.0mL of 0.30M KOH(aq)? c)if you start with a new 30.0mL sample of 0.20M C6H5COOH(aq), what volume of 0.20M NaOH(aq) is required to reach the halfway to the equivalence point? d) calculate the pH at the halfway point. e) what volume of 0.20M...
25.00 mL of 0.150M benzoic acid HC7H5O2 was titrated with 0.200 M NaOH. Calculate the pH at the following points. Ka for benzoic acid is 6.3x10-5 a. Before adding any NaOH b. Halfway to equivalence c. After adding 12.2 mL of the NaOH d. At the equivalence point Please answer all the parts!
7. A sample of 0.10 M C6H5COOH(aq) (benzoic acid) solution is titrated with 0.10 M NaOH(aq) solution. What is the pH of the solution at the equivalence point? Ka(C6H5COOH) = 6.46 x 10-5 8. A sample of 0.10 M C6H5CH2NH2(aq) (benzylamine) solution is titrated with 0.10 M HBr(aq) solution. What is the pH of the solution at the equivalence point? Kb(C6H5CH2NH2) = 2.24 x 10-5
A 25.0 mL sample of 0.150 M benzoic acid is titrated with a 0.150 M NaOH solution. What is the pH after the addition of 13.0 mL of NaOH? The Ka of benzoic acid is 6.3x10-5.
Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 × 10–5) with 0.0700 M NaOH Calculate the pH in the solution at equivalent point. a) 5.716 b) 8.284 c) 8.372 d) 5.628 e) 7.546
A student titrated a 100.0 mL sample of 0.100 M acetic acid with 0.050 M NaOH. (For acetic acid, Ka = 1.8 * 10^-5 at this temperature.) (a) Calculate the initial pH. (b) Calculate the pH after 50.0 mL of NaOH has been added. (c) Determine the volume of added base required to reach the equivalence point. (d) Determine the pH at the equivalence point?
Quest. 7 (30 pts). Benzoic acid (C6H5COOH), 40.0 mL of 0.150 M, is being titrated with 0.300 M potassium hydroxide (KOH). Calculate the pH a) before any addition of base, b) at the half neutralization (half equivalent) point, and c) at the equivalent point. The Ka of C6H5COOH is 6.5 x 10-5. Use the appropriate tables when necessary.
A 45.0 mL sample of 0.135 M acetylsalicylic acid (HC9H7O4, commonly known as aspirin) is titrated with 0.165 M NaOH. Determine each of the following and then use your answers to make a sketch of the titration curve. Ka of HC9H7O4 = 3.3 x 10-4 a. The volume of base required to reach the equivalence point. b. The initial pH. c. The pH when 25.0 mL of base has been added. d. The pH at the half-way point. e. The...
2. 20.00 mL of 0.270 M HA (K. = 7.2 x 10-4) was titrated with 0.300 M sodium hydroxide (3 + 3 + 2 + 3 + 3 + 3 + 12 = 29 points) a) Write the titration equation and calculate volume of NaOH needed to reach the equivalence point. ml b) At what volume of the titrant would pH=pKa? Why? c) pH at the equivalence point when the acid and base are neutralized will be ..choose one of...
A 50.0 mL sample of 0.25 M formic acid (HCOOH) aqueous solution is titrated with 0.125 M NaOH solution. Ka of HCOOH = 1.7 x 10−4. a. Calculate the pH of the solution after 50 mL of NaOH solution has been added. b. How many mL of 0.125 M NaOH need to be added to the sample to reach the equivalence point? What is the pH at the equivalence point?