Question

Please explain how to solve this. Thank you very much.

002 10.0 points Two identical small charged spheres hang in equilibrium with equal masses as shown in the figure. The length of the strings are equal and the angle (shown in the figure) with the vertical is identical 40 0.02 kg 0.02 kg

Answer 1

Solution)

Let spheres separation x = 2 * L sin θ = 2 * 0.12 sin 4 = 0.0167 m

If T is string tension, then

T sin θ - kqq/x2 = 0 => T sin θ = kq²/x²

T cos θ - mg = 0 => T cos θ = mg

So, tan θ = kq²/x² / mg

q² = mg x² tan θ / k

q = sqrt((mg x² tan θ / k))

q = sqrt((0.02 * 9.8 * 0.0414 * 0.0167* tan4/9 × 10^9))

= 3.24 * 10-8 C (Ans)

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Good luck!:)