A plate carries a charge of -3.9 µC, while a rod carries a charge of 2.5 µC. How many electrons must be transferred from the plate to the rod, so that both objects have the same charge?
N=?
Solution)
Here,
Q1 = -3.9 µC, Q2 = +2.5 µC
Let q = transferred negative charge
Q1 - q = Q2 + q
so q = (Q1 - Q2)/2 = -3.2 µC
Here,
number of electrons N = q/e, where e = -1.60*10^-19 C = -1.60*10^-13 µC
N = 3.2/1.60*10^-13 =2*10^13 (Ans)
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