Question

3. A pair of fair dice are tossed. Find the probability of getting (a) a total of 4. (b) at most a total of 4

Answer 1

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Sample Space

Total 36 Outcomes

a)

Probability = Favourable Outcomes/Total Outcomes

Dice 1	Dice 2	Sum
1	3	4
2	2	4
3	1	4

Hence, P = 3/36 = 0.0833 or 8.33%

b)

Dice 1	Dice 2	Sum
1	1	2
1	2	3
1	3	4
2	1	3
2	2	4
3	1	4

Hence, P = 6/36 = 0.1667 or 16.67%