spreadsheet solution? 5.35 Compare the alternatives shown on the basis of their capitalized costs using an...
Compare the alternatives shown below on the basis of their capitalized costs, using an effective rate 3% per quarter compounded quarterly Calculate the Capitalized Cost for each alternative and select the best option. Do not select until you have calculated the Capitalized Cost for each alternative. Alternative A Alternative B First Cost in $ -350,000 -700,000 Quarterly income, $/quarter +55,000 +45,000 Salvage value, $ +50,000 0.00 Life, in quarters 12 quarters Select Alternative A with CCA= +$778,733 Select Alternative B...
I cant get alternative y Problem 14.030: Compare alternatives by calculating their capitalized cost Compare the alternatives below on the basis of their capitalized costs with adjustments made for inflation. Use 3.2% per year. 10% per year and Alternative First cost,$ -19,000,000 13,500,000 -10,000 82,000 10 AOC, $per year25,000 Salvage value, $ Life, years 105,000 The capitalized cost for alternative X is s -19199107 The capitalized cost for alternative Y is $ 135762 。 Select alternative「-Y- O Problem 14.030: Compare...
3. Compare the alternatives shown below on the basis of their Annual Worth, using an interest rate of 12% per year. Alternative I Alternative II 160.000 25,000 First Cost 15.000 3,000 Annual Operating Cost 1,000,000 4,000 Salvage Value Life. Years
3. Compare the alternatives shown below on the basis of their Annual Worth, using an interest rate of 12% per year. Alternative I Alternative II First Cost 160,000 25,000 Annual Operating Cost 15,000 3,000 Salvage Value 1,000,000 4,000 Life, Years
Y 0.83 points Compare the alternatives below on the basis of their capitalized costs with adjustments made for inflation. Use i=12% per year and f= 3.8% per year. Alternative х First cost, $ -16,000,000 -14,500,000 AOC, $ per year -25,000 -10.000 Salvage value, $ 105,000 82,000 Life, years 10 eBook Hint Print The capitalized cost for alternative X is $ References The capitalized Click to select) IS Select alternativex
Question 3 (20 points) Compare the two mutually exclusive alternatives on the basis of their capitalized costs at i= 10% per year. First cost, $ Annual cost, $/year Salvage value, $ Life, years -110,000 –54,000 9,000 - 700,000 -15.000 2,000,000
Assume a mutually exclusive scenario. Compare three alternatives on the basis of their capitalized cost (CC) at i=10% per year, which is the best alternative in this scenario? • Alternative 1, AW = $87,500 and n = (forever) • Alternative 2, PW = -$895,000 and n = (forever) • Alternative 3, First cost (FC) of $900,000, annual operating savings of 3,000 per year, salvage = $200,000, and n = (forever) Alternative 2 Alternative 3 None of them Alternative 1 QUESTION...
Compare two alternatives, A and B. on the basis of a present worth evaluation using /= 10% per year and a study period of 8 years. Alternative A B First Cost $-19,000 $-46,000 Annual Operating Cost $-6,000 $-10,000 Overhaul in Year 4 $0 $-3,850 Salvage Value $1,200 $6,200 Life 8 years 4 years The present worth of alternative A is $ and that of alternative B is $ Alternative (Click to select) is selected.
Problem 05.023 Alternative Comparison - Different Lives Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 10% per year and a study period of 10 years. $ 40,000 $-6,000 D $-22.000 $-3,000 Alternative First Cost AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life, Years $-200 $-300 $7,000 10 $200 5 The present worth of alternative C is $ and that of alternative D is $...
Problem 05.023 Alternative Comparison - Different Lives Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 12% per year and a study period of 10 years. с $-44,000 $-12,000 $-34,000 $-7,000 Alternative First Cost AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life, Years $-1,500 $-1,200 $5,000 10 $1,200 5 The present worth of alternative C is $ -134497.32 and that of alternative D is $...