First Calculate the value of total amount of energy added to the ice
Energy = Power * time
=5 min x 60 s/min x 750 J/s = 225,000 J
we know that the ice cubes are at 0 deg C already,hence first we need to Calculate the heat required to melt the ice at 0 C
Heat required = mass in g x heat of fusion of water in J/g
= 441 g x 334 J/g
= 147,294 J
Now we substract this much of energy which is needed to convert all the ice to water from the value of total energy total, remaining amount of energy will increase the temperature ofwater
= 225000 - 147294 = 77,706 J
Then applying the formula of heat capacity of liquid water
delta H = m * C * (T - To)
C= specific heat capacity of water
C for liquid water is 4.18 J/gK
therefore the final temp T = H/(m*C) + To, where To = 0
so T = 77,706 J/(441g * 4.18 J/gK) = 42.1 degrees
PLEASE LEAVE THE POSITIVE FEEDBACK IF YOU LIKE THE SOLUTION
Four ice cubes at exactly 0 ∘C with a total mass of 53.5 g are combined with 130 g of water at 75 ∘C in an insulated container. (ΔH∘fus=6.02 kJ/mol, cwater=4.18J/g⋅∘C) If no heat is lost to the surroundings, what is the final temperature of the mixture? Express your answer using two significant figures.
Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of H2O(s) heat capacity of H2O(1) enthalpy of fusion of H20 37.7 J/(molK) 75.3 J/(mol·K) 6.01 kJ/mol Tf= 9.96
Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T, of the water after all the ice melts. heat capacity of H2O(s) heat capacity of H2O(1) enthalpy of fusion of H,O 37.7 J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol Ti =
Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T. of the water after all the ice melts. heat capacity of H,O() heat capacity of H,O(1) enthalpy of fusion of H,0 37.7J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol Ti = 24.99 "C Incorrect
Two 20.0-g ice cubes at –10.0 °C are placed into 255 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. heat capacity of water s = 37.7 heat capacity of water q =75.3 fusion = 6.01
ch.11
Four ice cubes at exactly 0 ºC with a total mass of 52.0 g are combined with 135 g of water at 90 °C in an insulated container. (AH..-6.02 kJ/mol. Cwater-4.18J/ 6C) V Part A If no heat is lost to the surroundings, what is the final temperature of the mixture? Express your answer using two significant figures. OVO AXT ? Given that the heat of freezing of water is-6.02 kJ/mol, that the heat capacity of H.O() is 752...
Two 20.0g ice cubes at -12.0^degree C are placed into 285g of water at 25.0^degree C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. heat capacity of H2O(s) is 37.7 J/mol*K heat capacity of H2O(l) is 75.3 J/mol*K enthalpy of fusion of H20 is 6.01 kJ/mol
Four ice cubes at exactly 0 ∘C with a total mass of 52.0 g are combined with 155 gof water at 90 ∘C in an insulated container. (ΔH∘fus=6.02 kJ/mol, cwater=4.18J/g⋅∘C) If no heat is lost to the surroundings, what is the final temperature of the mixture?
Four ice cubes at exactly 0 ∘C with a total mass of 54.0 g are combined with 125 g of water at 75 ∘C in an insulated container. (ΔH∘fus=6.02 kJ/mol, cwater=4.18J/g⋅∘C) If no heat is lost to the surroundings, what is the final temperature of the mixture?
Resources 40/3300 Two 20.0 g ice cubes at -21.0°C are placed into 225 g of water at 25.0'C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature. Ti of the water after all the ice melts. heat capacity of H,O(s) heat capacity of H, O(1) enthalpy of fusion of H, 0 37.7 J/mol K) 75.3 J/mol K) .01 kJ/mol 6 T Question Source MRG - General Chemi shout privacy policy c h ale