Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at...

Question

Question

Answer 1

Answer #1

heat gained by ice = heat lost by water

n1*c1*DT1 + n*DHfus = n2*c2*DT2

n1 = no of mole of ice = 40/18 = 2.222 mole

c1 = molar heat capacity of ice = 37.7 j/mol.c

DT1 = 0-(-12) = 12

n = no of mol of ice = 40/18 = 2.222 mole

DHfus = 6.01 kj/mol

n2 = no of mole of water = 225/18 = 12.5 mole

c2 = molar heat capacity of water = 75.3j/mol.c

DT2 = 25 - x c

2.222*37.7*12 +(2.222)*6.01*10^3 = 12.5*75.3*(25-x)

x = final temperature = 9.74 C

answer: Tf = 9.74 C

Add a comment

Answer 2

Similar Homework Help Questions

Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at...

Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T, of the water after all the ice melts. heat capacity of H2O(s) heat capacity of H2O(1) enthalpy of fusion of H,O 37.7 J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol Ti =
Two 20.0g ice cubes at -12.0^degree C are placed into 285g of water at 25.0^degree C....

Two 20.0g ice cubes at -12.0^degree C are placed into 285g of water at 25.0^degree C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. heat capacity of H2O(s) is 37.7 J/mol*K heat capacity of H2O(l) is 75.3 J/mol*K enthalpy of fusion of H20 is 6.01 kJ/mol
Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at...

Two 20.0 g ice cubes at -12.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, T. of the water after all the ice melts. heat capacity of H,O() heat capacity of H,O(1) enthalpy of fusion of H,0 37.7J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol Ti = 24.99 "C Incorrect

Two 20.0-g ice cubes at –10.0 °C are placed into 255 g of water at 25.0...

Two 20.0-g ice cubes at –10.0 °C are placed into 255 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. heat capacity of water s = 37.7 heat capacity of water q =75.3 fusion = 6.01
Resources 40/3300 Two 20.0 g ice cubes at -21.0°C are placed into 225 g of water...

Resources 40/3300 Two 20.0 g ice cubes at -21.0°C are placed into 225 g of water at 25.0'C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature. Ti of the water after all the ice melts. heat capacity of H,O(s) heat capacity of H, O(1) enthalpy of fusion of H, 0 37.7 J/mol K) 75.3 J/mol K) .01 kJ/mol 6 T Question Source MRG - General Chemi shout privacy policy c h ale
by Two 20 0g ice cubes at-13.0 ℃ are placed into 205 g of water at...

by Two 20 0g ice cubes at-13.0 ℃ are placed into 205 g of water at 25.0 ℃ Assuming no transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts heat capacity of H20(s) 37.7J(mol K) heat capacity of H20() 75.3 J(mol K) enthalpy of fusion of H2O 6.01 kJ/mol

Question 5 of 17 > Attempt 5 Two 20.0 g ice cubes at -21.0 °C are...

Question 5 of 17 > Attempt 5 Two 20.0 g ice cubes at -21.0 °C are placed into 285 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of H,O(s) heat capacity of H, 0(1) enthalpy of fusion of H,O 37.7J/(mol-K) 75.3 J/(mol.K) 6.01 kJ/mol View Menu Tp =
2005/2900 Resources 15 of 29 [ Give Up? Feedback Resume Attempt Two 20.0 g ice cubes...

2005/2900 Resources 15 of 29 [ Give Up? Feedback Resume Attempt Two 20.0 g ice cubes at -18.0 °C are placed into 285 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Ti, of the water after all the ice melts. heat capacity of H.O(s) heat capacity of H,O(1) enthalpy of fusion of H,O 37.7 J/(mol-K) 75.3 J/(mol-K) 6.01 kJ/mol 12.3 Publisher University Scies Question Source: MRG General Chemistry...
heat capacity of ?2?(?) 37.7 J/(mol⋅K) heat capacity of ?2?(?) 75.3 J/(mol⋅K) enthalpy of fusion of...

heat capacity of ?2?(?) 37.7 J/(mol⋅K) heat capacity of ?2?(?) 75.3 J/(mol⋅K) enthalpy of fusion of ?2? 6.01 kJ/mol Two 20.0‑g ice cubes at −14.0 °C are placed into 215 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts.

Two 20.0-g ice cubes at –13.0 °C are placed into 225 g of water at 25.0...

Two 20.0-g ice cubes at –13.0 °C are placed into 225 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature of the water after all the ice melts. PLEASE SHOW WORK!