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Please show all steps clearly!
_TOWARD HOME.PLATE IE RELEASES T KE BALL ATA PoN r 18.0.M. IT- G E ,TS--Te-74e-PLATE-ǐ
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Answer #1

Initial velocity vec{v}_i=v_xhat{x}+v_yhat{y}

There is no vertical component initially. That is v_y=0 and 5 125 18 3 m/s 150 kph 150 *

Acceleration has no horizontal component vec{a}=a_xhat{x}+a_yhat{y}=[0hat{x}+(-9.81)hat{y}],m/s

Displacement of ball Deltavec{r}=xhat{x}+yhat{y}=[18.0hat{x}+yhat{y}],m

Using only horizontal components, x=v_xt

18 =-t

Time taken 54 125

Using vertical components, y=v_yt+rac{1}{2}a_yt^2

059.81125 125) =-0.9154

That is, the ball drops by 0.9154,m by the time it reaches the plate.

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