given
q1 + q2 = 1343 uC
q1 = 1343e-6 - q2
Now,
F = 9e9 * q1q1 / 1.012
15.2 = 9e9 * q1q1 / 1.012
1.7228e-9 = q1q2
1.7228e-9 = (1343e-6 - q2)q2
1.7228e-9 = 1343e-6q2 - q22
- q22 + 1343e-6q2 - 1.7228e-9 = 0
solve this quadratic equation, we have
-1343e-6 +/- sqrt (1.8036e-6 - 6.89e-9) / -2
q2 = -1343e-6 +/- 1.3404e-3 / -2
q2 = 1.3417e-3 C (larger charge) and 1.3e-6 C (smaller charge)
if force was attractive, one of above two will be negative.
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