Here, μ = 269, σ = 11, x1 = 283 and x2 = 293. We need to compute P(283<= X <= 293). The corresponding z-value is calculated using Central Limit Theorem
z = (x - μ)/σ
z1 = (283 - 269)/11 = 1.27
z2 = (293 - 269)/11 = 2.18
Therefore, we get
P(283 <= X <= 293) = P((293 - 269)/11) <= z <= (293 -
269)/11)
= P(1.27 <= z <= 2.18) = P(z <= 2.18) - P(z <=
1.27)
= 0.9854 - 0.898
= 0.0874
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