Question

IVVICII Ulslal ILS A toroidal solenoid has 560 turns, cross-sectional area 6.90 cm", and mean radius 4.10 cm. Part A Calcualte the coil's self-inductance. Express your answer in henries. A2 * O O ? | L- Submit Request Answer Part B If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms, calculate the self-induced emf in the coil. Express your answer in volts. o AS O O ?
Please solve for A,B and C

Answer 1

(a) Coil's sey Inductance - » N- 560 turns A = 6.90 x 10+ m² = 0.0 41m =) Let's me sex inductance eq"; A = N o = N (B. A) = N(Mon I) A T = NM NA - NM A oL = (560)X ( 41. x40-7) (6.9 X 10-4) 2KX 0.041 218 u 2TS L- 10.55 x 10+++

(6) Induced End; Er? - TOAS Induced rug ΛΙ 2.00 5.00 at 0,003 & E= - L di at = - (10.55 X 10-4) (-10%) – 10.55 X 10-1 2 1.05 V Aus (c) So, the current is decuasing, so the Induced and will have the same direction that of current lie. roun a to b. as