Question

ΓarA A toroidal solenoid has 600 turns, cross-sectional area 6.90 cm", and mean radius 4.50 cm. Calculate the coil's self-Inductance. Express your answer in henries. IVO AXO L = H Submit Request Answer Part B If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms, calculate the self-induced emf in the coil. Express your answer in volts. GAS ? V Submit Request Answer Part C The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a? O From a to b O From b to a Submit Request Answer

Answer 1

8- 4.50cm N=600, A= 6-90cm2 A = 6.90x104m2 8=4.50mx10m self inductance of toroidal solenoid. L = MONZA 2TR L- UTX107x (600) ²6.90x104 25 x 4.50x 10-2m L = 1.104 m H dI = - 1000 Amply dt (2-5) = -3 Amp da dt - 3 ms=3X20-3 ser nagnetic field in the torodial solenoid B = HONI id=NBA ma 2TR d = HONDA 2TR self inductance e.m-f de dt -hdr e二一 MONZA 2TR y de dt dt e= X Looo UT X10 X600) 2 x 6.90x104 2AX 4.50X102 e- L. Lou volt 'C currend is decreasing with respect to time then self inductance current trying to increase the current in solenoid then direction of induced current will be a to b