Question

You have 10 uM (1*10^-6M) of Tartaric Acid. pKa1=2.89, pKa2=4.4

Calculate pH.

Answer 1

fuen MolaaPty tartanic acrd (40 loHM ox foM Construc ttna lce table for the reacfon CAM0620(L) 4M0 t go Caa) Caa) Caa) toxiob htHa +x CM) -X Change tquflfb Cloxiox) 9iuon Pka= 2-89 2-89 kailo O OO1288 24955 The exp Nssfon fo Ka ven by M50Cgo Kai- O oo128824955 n2 loxTob-x) O. Oo128 8 24 55 28824955 x8 O oo12 88 2456 X 2882 4155 Xto-o to Oo12 88 24955x

Solveg far xtoM 9.92356 Xt Thug, [gr C50 . 1235cx0 Constuctg lce tablefor the Reacon gda 4.92356xi0 C450pca2oe) Ha 9.9235 xio Change .9235xio) Equilbriu -9235txio-x) X(o The expneesPon f ka2 iveuby Kar .235txio ) C9.9235 xa-) gPuen: Pkaz 4.f Pkar kaz- lo = 3- 981077I xi 4.92352x1 n Toue 3.9810717 xio .92357x0-) 3.9810441xio (9.92352xio-) 9.92 35xi1t

3.950 6404 xlo 3.1810 7171 xi0x .92 358 x10 + nt9.92352xiox +3.98167171 x10 - 3.950 640 4 x 1o0 t 4.173 4 271 xio 3.950 6404x10 Solving frx 6.16741 xioM Thus, Cngot 1.1235 xio tx 92 352 xio 6.9641 X0 M xiosM = 1. 689017 x PlogCH30r log .689097 xio5 4.7723 454 = 4.17