Calculate the heat energy released when 10.7 g of liquid mercury at 25.00 °C is converted to solid mercury at its melting point.
Initial temperature (Ti) = 25.00 oC
Final temperature (Tf) = Melting point of mercury = - 38.83 oC
Temperature difference, = (Tf - Ti) = ( - 38.83 oC - 25.00 oC) = - 63.83 oC
Mass of mercury (m) = 10.7 g
Specific heat capacity of mercury (s) = 0.140 J/g.oC
Now, heat energy released = m x s x
= 10.7 g x 0.140 J/g.oC x (- 63.83 oC)
= - 95.6 J (the negative sign implies that the heat is released)
Calculate the heat energy released when 10.7 g of liquid mercury at 25.00 °C is converted...
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