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1. At 1 atm, how much energy is required to heat 35.0 g H2O(s) at −10.0...

1. At 1 atm, how much energy is required to heat 35.0 g H2O(s) at −10.0 ∘C to H2O(g) at 137.0 ∘C? Use the heat transfer constants found in this

Quantity per gram per mole
Enthalpy of fusion 333.6 J/g 6010. J/mol
Enthalpy of vaporization 2257 J/g 40660 J/mol
Specific heat of solid H2O (ice) 2.087 J/(g·°C) * 37.60 J/(mol·°C) *
Specific heat of liquid H2O (water) 4.184 J/(g·°C) * 75.37 J/(mol·°C) *
Specific heat of gaseous H2O (steam) 2.000 J/(g·°C) * 36.03 J/(mol·°C) *

Calculate the heat energy released when 11.4 g of liquid mercury at 25.00 °C is converted to solid mercury at its melting point.

2.29jk/mole for the last colum-it doesnt copy

Constants for mercury at 1 atm
heat capacity of Hg(l) 28.0 J/(mol⋅K)
melting point 234.32 K
enthalpy of fusion
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