A 15.000 g water sample contaminated with mercury (I) is reacted with excess sodium chloride to...
A 15.000 g water sample contaminated with mercury (I) is reacted with excess sodium chloride to produce 75.6 mg of precipitate. What was the mass percent of mercury in the sample?
Homework Answers
mass of precipitate = 75.6mg = 0.0756
Hg(l) + 2NaCl(aq) ----------> HgCl2(s) + 2Na(s)
1 mole of HgCl2 produced from 1 mole of Hg(l)
271.52g of HgCl2 produced from 200.59g of Hg(l)
0.0756g of HgCl2 produced from = 200.59*0.0756/271.52 = 0.05585g of Hg(l)
mass percent of mercury in the sample = 0.05585*100/15 = 0.372% >>>>answer
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