Homework Answers
g = GM/r^2
where g = acceleration due to gravity
G = gravitational constant
M = mass of earth
R = raidus of earth
9.8 = G*5.983*10^24 / (6.378*10^6)^2
G = 6.663*10^-11 m3⋅g−1⋅s−2
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5. Use your closest value to calculate a value of the universal gravitational constant G, where...
Urstane Vs. Time y 58.77 -Velety Y. Tie Valoeity Ys.Tme Use the eguation of the curve...
Urstane Vs. Time y 58.77 -Velety Y. Tie Valoeity Ys.Tme Use the eguation of the curve to find the acceleration g Note: The quantity that will give g is (12) the coefficient of the t? term. In addition, in order tó convert this value from units of em/0.017s/0.17s to units of em/s2, this number must by multiplied by 60 X 6 360. 3. Calculate relative error in the value of g obtained in Calculations 1 and the accepted value of...
At what altitude above the surface of the carth the acceleration of gravity (free fall) is...
At what altitude above the surface of the carth the acceleration of gravity (free fall) is 0.875 of its value at the surface? 7. Note that: Radius of Earth is Re 6.37 x 106 m Mass of Earth is Me-5.98 x 1024 kg Gravitational Constant G- 6.67 x 101l N.m'/kg
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity...
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity at the earth's surface g. Therefore, calculate g from G using the relationships given below. Justify the choice of units for G (Nm kg?). F= mg The mass of the earth is 5.98 x 1024 kg, it's radius is Tg = 6.38 x 10 m, and G = 6.67 x 10-11 Nm?kg (10 marks) (b) Explain, including performing the integral, how the work done...
The value of g at the Earth's surface is about 9.81 m/s2. The the mass of...
The value of g at the Earth's surface is about 9.81 m/s2. The the mass of the Earth = 5.98 x 1024 kg and the radius of the Earth is 6.37 x 106 m. 1) Calculate the value of g for a satellite that is orbiting in a circle at an altitude equal to 3 Earth radii. g =
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earth is r.-6.38% 106 m and the gravitational constant G-667x 10-11 N m4kg2 and the Earth's...
earth is r.-6.38% 106 m and the gravitational constant G-667x 10-11 N m4kg2 and the Earth's mass is m.-598 × 1024 kg Potential cotan0 asin0acosO Feedback 1 Mar 08, 2019 11:36 PM V 60215
Draw a diagram and please answer both parts What was the speed of a space shuttle...
Draw a diagram and please answer both parts What was the speed of a space shuttle that orbited Earth at an altitude of 3 x 105 m? Mass of earth = 5.98 x 1024 kg; Radius of earth = 6.38 x 106 m Universal gravitational constant, G = 6.67 x 10-11 N m2 / kg (b) What is its period?
Consider a 495 kg satellite in a circular orbit at a distance of 3.02 x 104...
Consider a 495 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 103 km and Me = 5.97 x 1024 kg,...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 107 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 109 km and Me = 5.97 x 1024 kg,...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are Re = 6.37 % 10% km and Me = 5.97 x 1024 kg,...
Urstane Vs. Time y 58.77 -Velety Y. Tie Valoeity Ys.Tme Use the eguation of the curve to find the acceleration g Note: The quantity that will give g is (12) the coefficient of the t? term. In addition, in order tó convert this value from units of em/0.017s/0.17s to units of em/s2, this number must by multiplied by 60 X 6 360. 3. Calculate relative error in the value of g obtained in Calculations 1 and the accepted value of...
At what altitude above the surface of the carth the acceleration of gravity (free fall) is 0.875 of its value at the surface? 7. Note that: Radius of Earth is Re 6.37 x 106 m Mass of Earth is Me-5.98 x 1024 kg Gravitational Constant G- 6.67 x 101l N.m'/kg
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity at the earth's surface g. Therefore, calculate g from G using the relationships given below. Justify the choice of units for G (Nm kg?). F= mg The mass of the earth is 5.98 x 1024 kg, it's radius is Tg = 6.38 x 10 m, and G = 6.67 x 10-11 Nm?kg (10 marks) (b) Explain, including performing the integral, how the work done...
ars nly shrank to a tenth mass What would o the Sun? d sphere to a and mass How where G-untversal gravitational constant: G-6.67x101 N k m-3 kg- the mass of the baby M-either the mass of Mars or the obstetrician, and r-the separation between the baby and either Mars or the doctor at the instant of birth th bored from one of the Earth, and seball down this e surface What Questions 1. Calculate Fr. the force on the...
earth is r.-6.38% 106 m and the gravitational constant G-667x 10-11 N m4kg2 and the Earth's mass is m.-598 × 1024 kg Potential cotan0 asin0acosO Feedback 1 Mar 08, 2019 11:36 PM V 60215
Consider a 495 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 103 km and Me = 5.97 x 1024 kg,...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 107 km above the Earth's surface. The radius of the Earth and the mass of the Earth are RE = 6.37 x 109 km and Me = 5.97 x 1024 kg,...
Consider a 455 kg satellite in a circular orbit at a distance of 3.02 x 104 km above the Earth's surface. What is the minimum amount of work W the satellite's thrusters must do to raise the satellite to a geosynchronous orbit? Geosynchronous orbits occur at approximately 3.60 x 104 km above the Earth's surface. The radius of the Earth and the mass of the Earth are Re = 6.37 % 10% km and Me = 5.97 x 1024 kg,...
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