The value of g at the Earth's surface is about 9.81 m/s2. The the mass of the Earth = 5.98 x 1024 kg and the radius of the Earth is 6.37 x 106 m.
1) Calculate the value of g for a satellite that is orbiting in a circle at an altitude equal to 3 Earth radii. g =
The value of g at the Earth's surface is about 9.81 m/s2. The the mass of...
At what altitude above the surface of the carth the acceleration of gravity (free fall) is 0.875 of its value at the surface? 7. Note that: Radius of Earth is Re 6.37 x 106 m Mass of Earth is Me-5.98 x 1024 kg Gravitational Constant G- 6.67 x 101l N.m'/kg
22. An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4000 miles). At this location, the acceleration due to gravity 13 what factor times the value of g at the Earth's surface? a. There is no acceleration since the satellite is in orbit. b. 2 c. 1/2 d. 1/4 23. An object that is orbiting the Earth at a height of three Earth radil from the center of the Earth has a...
A particular satellite was placed in a circular orbit about 163 mi above Earth. (a) Determine the orbital speed of the satellite. m/s (b) Determine the time required for one complete revolution. min 1024 kg.) An artificial satellite circling the Earth completes each orbit in 119 minutes. (The radius of the Earth is 6.38 x 106 m. The mass of the Earth is 5.98 (a) Find the altitude of the satellite. m (b) What is the value of g at...
A satellite is in a circular orbit about the Earth at a distance of four (4) Earth radii above the surface of the Earth. What is the velocity of the satellite? (Earth's mass: ME = 5.98 x 1024 kg; the radius of the Earth: 6.4 x 106m ; G = 6.67 x 10-11 Nm2/kg2 ). A) 4,072.5 m/s B)3,530.5 m/s C)5,582.2 m/s D)7,465.9 m/s
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: T2 =(4π^2/GMs)r^3 so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) _______________h (b) Find the speed of the satellite. _________km/s (c) Find the acceleration of the satellite....
A satellite circles the earth in an orbit whose radius is five times the earth's radius. The earth's mass is 5.98 1024 kg, and its radius is 6.38 106 m. What is the period of the satellite?
A 270 kg satellite is orbiting on a circular orbit 6180 km above the Earth's surface. Determine the speed of the satellite. (The mass of the Earth is 5.97×1024 kg, and the radius of the Earth is 6370 km.)
A satellite m = 500 kg orbits the earth at a distance d = 218 km, above the surface of the planet. The radius of the earth is re = 6.38 × 106 m and the gravitational constant G = 6.67 × 10-11 N m2/kg2 and the Earth's mass is me = 5.98 × 1024 kg. What is the speed of the satellite in m/s?
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
Acceleration due to gravity on board of your spaceship that orbits Jupiter is 25.89 m/s. How high is your spaceship above Jupiter's cloud tops? Express your answer in kilometers and round it to the nearest integer. M Jupiter = 1.90 x 104 kg; R Jupiter = 69,911 km. Your cosmic journey brought you into the vicinity of a neutron star. In fact, you are orbiting this neutron star at an orbital distance of 22.424 kilometers. The neutron star has mass...