A satellite circles the earth in an orbit whose radius is five times the earth's radius. The earth's mass is 5.98 1024 kg, and its radius is 6.38 106 m. What is the period of the satellite?
Period of satellite is given as
T = 2*pi*sqrt(r^3/(G*M)) = 2*(22/7)*sqrt((5*6.38*10^6)^3/(6.67*10^(-11)*5.98*10^24)) = 56705.7 sec
A satellite circles the earth in an orbit whose radius is five times the earth's radius....
A satellite circles the earth in an orbit whose radius is 2.84 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 10m. What is the period of the satellite? Number 187.01 Units 5
A satellite circles the earth in an orbit whose radius is 4.67 times the earth's radius. The earth's mass is 5.98 times 10^24 kg, and its radius is 6.38 times 10^6 m. What is the period of the satellite? Number Units the tolerance is +/-2%
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: T2 =(4π^2/GMs)r^3 so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) _______________h (b) Find the speed of the satellite. _________km/s (c) Find the acceleration of the satellite....
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A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
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