A 10cm×10cm×10cm wood block with a density of 650 kg/m3 floats in water. |
Part A What is the distance from the top of the block to the water if the water is fresh? .
If it's seawater? Suppose that ρ=1030kg/m3. |
(a).
density of fresh water is ρ_water = 1000 kg/m³
ΣF = 0
- (ρ_wood)g(V_wood) + (ρ_water)g(v_wood) = 0
(v_wood)/(V_wood) = (ρ_wood)/(ρ_water)
(10 * 10 * h)/(10 * 10 * 10) = (650)/(1000)
h = 6.5 cm
the distance from the top of the block to the water is 10 - 6.5 =
3.5 cm....Answer.
(b).
density of seawater is ρ_sea = 1030 kg/m³
(v_wood)/(V_wood) = (ρ_wood)/(ρ_sea)
(10 * 10 * h')/(10 * 10 * 10) = (650)/(1030)
h' = 6.31 cm
the distance from the top of the block to the water is 10 - 6.31 =
3.7 cm...Answer.
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