Calculate the pH of 3.5x10-7 M NaOH
Calculate the pH of a 0.13 M solution of HClO, with K_a = 3.5x10^{−8}
Calculate the pH of a 0.13 M solution of HClO, with K_a = 3.5x10^{−8}.
Calculate the pH of a 0.410 M aqueous solution of hypochlorous acid (Hcio, Ka -3.5x10). pH =
Calculate the pH of the following solution: [H3O+] = 3.5x10–8 M. with proper significant figures
Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide. The volume of 21.70 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) the concentration of the cyanic acid solution before the titration b) the pH of the cyanic acid solution before the titration c) the pH of the solution at half-equivalence point
Calculate pH for a weak acid/strong base titration. Determine the pH during the titration of 67.3 mL of 0.419 M hypochlorous acid (K-3.5x10-) by 0.419 M NaOH at the following points. (a) Before the addition of any NaOH (b) After the addition of 15.0 mL of NaOH (c) At the half-equivalence point (the titration midpoint) (d) At the equivalence point (e) After the addition of 101 mL of NaOH
3. Calculate the equilibrium pH of NaOH solutions containing (a) 104 M NaOH, (b) 10-8 M MaOH.
Calculate [OH -] and pH for each of the following solutions. (a) 0.0010 M NaOH [OH-] = M pH = (b) 0.0267 g of LiOH in 550.0 mL of solution [OH -] = M pH = (c) 69.4 mL of 0.00138 M Sr(OH)2 diluted to 600 mL [OH -] = M pH = (d) A solution formed by mixing 49.0 mL of 0.000590 M Sr(OH)2 with 77.0 mL of 4.2 x 10-3 M NaOH [OH -] = M pH =
Calculate [OH -] and pH for each of the following solutions. (a) 0.0013 M NaOH [OH-] = ____M pH =_____ (b) 0.0571 g of CsOH in 540.0 mL of solution [OH -] ____= M pH =____ (c) 11.6 mL of 0.00247 M Ba(OH)2 diluted to 800 mL [OH -] = ___ M pH =___ (d) A solution formed by mixing 82.0 mL of 0.000500 M Ba(OH)2 with 54.0 mL of 6.4 x 10-3 M NaOH [OH -] = ___M pH...
Neglecting activities, calculate the pH of a solution containing 0.013 M NaOH plus 0.0120 M LiNO3. 12.11 pH Using activities, re-calculate the actually pH of the solution. ?