Question

Calculate [OH -] and pH for each of the following solutions.

(a) 0.0010 M NaOH

[OH-] = M pH =

(b) 0.0267 g of LiOH in 550.0 mL of solution

[OH -] = M pH =

(c) 69.4 mL of 0.00138 M Sr(OH)2 diluted to 600 mL

[OH -] = M pH =

(d) A solution formed by mixing 49.0 mL of 0.000590 M Sr(OH)2 with 77.0 mL of 4.2 x 10-3 M NaOH

[OH -] = M pH =

Answer 1

اه هم م ه ه . ) Naon M 10-3 Lo-) - (5-3 5- ) ر ا م log 10-3 per pon = // = 3 = ۱۶ = م/ 3=p خود , ره کی د هکر ادا 3، ۵ . 04 رو، ومه عك کو3 وی د-96 تیمورد /. 2 05 م ۔ ( م/] , ( 0,00 2 به همه لا - - و 8 , pon a قلاع ووهله ام

e fordilution M, V. = More 69.480.00 138 = M2 x bow feyx0.00138 - D = 60 ots Ooools -)=2xo.ooo15 pon = -log[on- ] реч - пр. во 0,3) on z 3.50 .ph - 14-3.51 ton toolg vituo • - D (on}= N. Ut on Nou, t Nr Uz 0.0005 gx 49x2 + 4.2x15377 77 +49 • bon the može z Tony = 0.05782 10.32240 pont 2.52 127 - phI 14-2.52 0.0ogo
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