Question

3. What volume of 0.025 M NaOH will be required to reach the endpoint in a titration with 25.00 ml of 0.10 M HCI? Show your work with units and correct significant figures. Circle your answer. 4. Calculate the molarity of a sodium hydroxide solution if 25.00 mL 0.100 M maleic acid requires 22.10 ml of NaOH to reach the endpoint. Show your work with units and correct significant figures. Circle your answer. 5. The following data were collected in the titration of 10.0 mL of 0.10 M weak acid, HA, with 0.10 M NaOH solution. Tabulate and plot graph on graph paper: titration curve, and find the equivalence point. mL 0.10 M NaOH OH 0.00 3.00 1.00 4.05 2.50 4.52 5.00 5.00 7.50 5.48 8.75 9.50 9.75 6.59 9.90 7.00 10.00 8.85 10.10 10.70 10.25 10.50 11.39 12.75 12.08 15.00 12.30 5.85 6.28 11.09

Answer 1

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Q3 As NaOH 2 Hal both are monop sotie And so Mseng Malarity equation MV, = M2 V2 | Mia Malarity of And Vi= Volume of And 0.1 M X 2 5 = 0.025 X VG Ma = Molarity of base Va = to Ool MX 25-10ome Va - Volume of base 0.025 So loo me Na Oh is used CH=CH- @ 2 Now As maleic And is none As Acid is dipsotic Acid Normality - 2 x Molarity As Accelety As 2 x oolo Normality = 0.2 NIVI = Nz V₂ Now = N, X 2 201= 0o 2x 25m Ni = 0.226 AS Normality - Malarity Na OH is mono base so So Malarity of Auct = Noon 0.22 6M Ang