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A cylinder of mass 6.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed

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Answer #1

a) kE = 4 mu?: 176x102= (1475) 6) KE = 1 I ² = 1 1 1 8² x 2 = 1 mv² x 6xe ² (33.55 () Total Energy = kEfron & KE setatural =

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Circle answers please A cylinder of mass 6.0 kg rolls without slipping on a horizontal surface....
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