A parallel‑plate capacitor has plates of 4.70 cm by 4.60 cm. The plates are separated by a 0.500-mm ‑thick piece of paper. What is the capacitance ? of this capacitor? The dielectric constant for paper is 2.5.
Area is,
A = 0.047 m x 0.046 m = 0.002162 m2
d = 0.5x10-3 m
dielectric constant K = 2.5
hence, capacitance is,
C = KAϵo/d = 9.57x10-11 F
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A parallel‑plate capacitor has plates of 4.70 cm by 4.60 cm. The plates are separated by...
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