Question

100.0 mL of 0.800 M AgNO3(aq) and 100.0 mL of 1.025 M BaCl2 (aq) are combined and allowed to react according to the following equation: 2AgNO3 (aq) + BaCl2 (aq) + 2AgCl (s) + Ba(NO3)2 (aq) a. Determine the theoretical yield (in g) of AgCl(s). b. What is the limiting reagent?

Answer 1

JAGNO, (AQ)+ Bau, (q) — 219C1 (8)4 (or)(ar) 2 mole of Ag No, peace co o le ol Paul to form annote of Azul and I mole ct BRINO3)2. Molan'ty = no ot moleso+solute Volume of Solutions du (00.0 sul 6+ 0.800 M AS NO no ot pudes od ASNO, = Molanty Xorlumeiul 30.800 M X 100.0L 1000 : 0800 ml x 100.0 TODO = 0.08 mole. loaoul of 1.025 M Back no of moles of Back = molarity x volume in 1.025 M X 100.0L looo = 1.025 me 4000 4 = 0.1025 101, imole of Bach resuired 2 mole of AS NO 0.08 role of ASNO ? no otudy of Badle required = 0.081 -0.04 mole

But 0.1025 mole of Bach is present. te Back is excers. It is excess by 0.1025 -0.04 = 0.0625 mole. - AgNO3 is limitius reagent Consumed totally in leic reactions > 2 mole of Aga istormed. 2 mole of AS NO 2x170 3 07 AS No → 2X143.5 9 of ASLI is tormed 0.08 note = 0.08x1708 CH AS No -> ?? Mase of Agu formed = 0.08x136 x7x14305 2x170 = 11:48 g of Asu tovmed. Agu. This is the oretical yield of @ Theoretical Yield of Agu = 11.489 AgNO, is limiting reagent a more