Question

1259 2 0 349H₂ = $.675 mol 10. A 5.95-g sample of AgNO3 is reacted with excess BaCl2 according to the equation 2AgNO3(aq) + BaCl2(aq) + 2AgCl(s) + Ba(NO3)2(aq) to give 4.48 g of AgCl. What is the percent yield of AgCl?

Answer 1

according to balanced reaction

2 x 169.87 g AgNO3 gives 2 x 143.32 g AgCl

5.95 g AgNO3 gives 5.95 x 2 x 143.32 / 2 x 169.87 = 1705.508 / 339.74 = 5.02 g AgCl

theoretical yield of AgCl = 5.02 g

actual yield = 4.48 g

% yield = (actual yield / theoretical yield) x 100

% yield = (4.48 / 5.02) x 100

% yield = 89.2 %