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4What is the minimum required mass of NaOH that would be required to completely convert 121 mL of methyl salicylate to salicy
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Answer #1

Question 4.

The minimum mass of NaOH required = Same as the moles of methyl salicylate

= (1.21 mL * 1.17 g.mL-1/152.1494 g.mol-1) * 40 g/mol = 0.3722 g

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