Question

Ask Your Teacher G My Notes SerCP11 8.4.P.044 -/2 polnts A bicycle wheel has a diameter of 64.4 cm and a mass of 1.87 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 121N is applied tangent to the rim of the tire. (a) What force must be applied by a chain passing over a 8.93-cm-diameter sprocket in order to give the wheel an acceleration of 4.60 rad/s N (b) What force is required if you shift to a 5.59-ccm-diameter sprocket? kN Need Help? Read

Answer 1

vv I Thy is Gwen Diameth of whil IT = 0.89 24 Nom 1 am to Inutia D=64.4CM = 0.64AM bet Resisting torque due to Mass of whul (M)=1.87kg. applied resistive yerel on whel. Resisthe force (F)= 121N TR= fix Radius of whell. Tartu Angular acceleration TR=121x/0.644= 38.962 NM] requered (or) = 4.60 Rad/s2 Total torque required to get Diameter of sprocket (d) =893cr required acceleration T-IT +TR=0+8924+30.962 Id=o. 0893m} IT=39.8544 Nom. I @ Moment of Inertia of what Let F2 & force applied by chaine about a sus of rotation T= FX Radius of sprocket 390 544= F I = MR? (This is a hoop) Fa> 892: 5957N Ans- I= 1:37x (0-649) of or sprockat diametu (d) = 5.59 cm I= 0.1941cg m2] 39.0544 Torque required to genuate due to F3 = 1425.92N requered acceleration due to Ary-5 T=Id=0194 x 4160 s said 08559T = 1425-92