The lowest pressure attainable using the best available vacuum techniques is about 10−12N/m2.
1. At such a pressure, how many molecules are there per cm3 at 11 ∘C?
Express your answer using two significant figures.
let the numner of moles per cm^3 is n
P = 1 *10^-12 Pa
Using ideal gas equation
P * V = n * R * T
10^-12 * 10^-6 = n * 8.314 * (11 + 273)
solving for n
n = 4.235 *10^-22
number of molecules per cm^3 = NA * n
number of molecules per cm^3 = 4.235 *10^-22 * 6.022 *10^23
number of molecules per cm^3 = 255
the number of molecules per cm^3 is 255
The lowest pressure attainable using the best available vacuum techniques is about 10−12N/m2. 1. At such...
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