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Calculate the number of collisions per second of one hydrogen molecule at 21 °C and 8.00 bar. The diameter of a hydrogen molecule is 270 pm collisions-s 8.01 x107 Z =

Answer 1

This question is explained as follows:

U Sol We have to calculate the number of collisions per second of one hydrogen molecule at 21°c and 8:00 bar The diameter of a hydrogen molecule is 270pm. i'l', - 20A Collide Collision diameter 36 = ratra or s=2rA = 270 pm Orolo-12 O 270 - {1pm = 10-12 m} theory; we know, the no. of collisia unit time is - It se u No 2 I Now, acc. to collision per unit volume per TAA = - N is where, & is collision diameter, u es 8KGT and ITMA caverage speed) Drogadro number.

- Let us calculate ū» 18xKAT m = mass - mass of single molecule i e; for H₂ , MA=2 KB = Bolt 3 - Boltzmann constant = 1.38×10 JIK = 21°C = 273 +21= 294 K 8 m]:38 x 10-29 x 294 3.14 x 2 32 45.76 x 10-23 6.28 (324.576 X 10 22 6.28 51.684 x 10-22 no u = 7.189 X 10-11 m/sec. of collisions per second ZAA - X3:14 X (2704 104)7189 X 10-11 (6.02 x 10²3) ² - x 5963739119 22 X 10 24 x 10 x 10th 1.41 42296022.6398 x 10 ZAA = 4.2296 X 1048 Aus Total no of collisions per second is 4.2296% 1018 Ang