Question

In the figure R1 110 Ω, R2 = R3 resistance 3, and (e) resistance 4? 59.0 Ω, R4-73.6 Ω, and the ideal battery has emf ε 6.00 V. (a) what is the equivalent resistance? what is i in (b) resistance 1, (c) resistance 2, (d) Ri Ri Ry Rs (a) Number (b) Number (c) Number (d) Number (e) Number Units Units Units Units

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Answer #1

First of all, to calculate the equivalent resistance of the circuit, I have shown the simple circuit. Hence it is clear that R2, R3, and R4 are parallel to each other and there answer is in series with the resistance R1.

To fine the current in different resistances first of all calculate total current flowing from the battery. The same total current will flow through R1 but then current will be distributed in other all three resistance which are parallel.

Scanned sheet is attached for detail solution and answers are marked with red Pen.

Eqivslent Ciscuit Given Crui 2 3 resistance 2 453 59 73.6 , 21.06 Solvinį this eg uation R Nlow R and Rase in sesies 4hemefore (a Equivalent Resistane131 06 Given E = 6.co V Cument wing ftrom ba He f 131,06 (by Cuent in04s Anbere Since R, R R4 are barellel hence potenial di fterene. (cacucs them is same as calculae64V Cume叶in K.-K-0.964-00163 Ampere d) 59

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